3.8.55 \(\int \frac {x^{7/2} (A+B x)}{(a^2+2 a b x+b^2 x^2)^{5/2}} \, dx\)

Optimal. Leaf size=306 \[ \frac {x^{9/2} (A b-a B)}{4 a b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {x^{7/2} (A b-9 a B)}{24 a b^2 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {35 (a+b x) (A b-9 a B) \tan ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{64 \sqrt {a} b^{11/2} \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {35 \sqrt {x} (a+b x) (A b-9 a B)}{64 a b^5 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {35 x^{3/2} (A b-9 a B)}{192 a b^4 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {7 x^{5/2} (A b-9 a B)}{96 a b^3 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}} \]

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Rubi [A]  time = 0.15, antiderivative size = 306, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 6, integrand size = 31, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.194, Rules used = {770, 78, 47, 50, 63, 205} \begin {gather*} \frac {x^{9/2} (A b-a B)}{4 a b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {x^{7/2} (A b-9 a B)}{24 a b^2 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {7 x^{5/2} (A b-9 a B)}{96 a b^3 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {35 x^{3/2} (A b-9 a B)}{192 a b^4 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {35 \sqrt {x} (a+b x) (A b-9 a B)}{64 a b^5 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {35 (a+b x) (A b-9 a B) \tan ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{64 \sqrt {a} b^{11/2} \sqrt {a^2+2 a b x+b^2 x^2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(x^(7/2)*(A + B*x))/(a^2 + 2*a*b*x + b^2*x^2)^(5/2),x]

[Out]

(35*(A*b - 9*a*B)*x^(3/2))/(192*a*b^4*Sqrt[a^2 + 2*a*b*x + b^2*x^2]) + ((A*b - a*B)*x^(9/2))/(4*a*b*(a + b*x)^
3*Sqrt[a^2 + 2*a*b*x + b^2*x^2]) + ((A*b - 9*a*B)*x^(7/2))/(24*a*b^2*(a + b*x)^2*Sqrt[a^2 + 2*a*b*x + b^2*x^2]
) + (7*(A*b - 9*a*B)*x^(5/2))/(96*a*b^3*(a + b*x)*Sqrt[a^2 + 2*a*b*x + b^2*x^2]) - (35*(A*b - 9*a*B)*Sqrt[x]*(
a + b*x))/(64*a*b^5*Sqrt[a^2 + 2*a*b*x + b^2*x^2]) + (35*(A*b - 9*a*B)*(a + b*x)*ArcTan[(Sqrt[b]*Sqrt[x])/Sqrt
[a]])/(64*Sqrt[a]*b^(11/2)*Sqrt[a^2 + 2*a*b*x + b^2*x^2])

Rule 47

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + 1)), x] - Dist[(d*n)/(b*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d},
x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && LtQ[m, -1] &&  !(IntegerQ[n] &&  !IntegerQ[m]) &&  !(ILeQ[m + n + 2, 0
] && (FractionQ[m] || GeQ[2*n + m + 1, 0])) && IntLinearQ[a, b, c, d, m, n, x]

Rule 50

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + n + 1)), x] + Dist[(n*(b*c - a*d))/(b*(m + n + 1)), Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !IntegerQ[n] || (G
tQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinearQ[a, b, c, d, m, n, x]

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 78

Int[((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> -Simp[((b*e - a*f
)*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/(f*(p + 1)*(c*f - d*e)), x] - Dist[(a*d*f*(n + p + 2) - b*(d*e*(n + 1)
+ c*f*(p + 1)))/(f*(p + 1)*(c*f - d*e)), Int[(c + d*x)^n*(e + f*x)^(p + 1), x], x] /; FreeQ[{a, b, c, d, e, f,
n}, x] && LtQ[p, -1] && ( !LtQ[n, -1] || IntegerQ[p] ||  !(IntegerQ[n] ||  !(EqQ[e, 0] ||  !(EqQ[c, 0] || LtQ
[p, n]))))

Rule 205

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]*ArcTan[x/Rt[a/b, 2]])/a, x] /; FreeQ[{a, b}, x]
&& PosQ[a/b]

Rule 770

Int[((d_.) + (e_.)*(x_))^(m_.)*((f_.) + (g_.)*(x_))*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Dis
t[(a + b*x + c*x^2)^FracPart[p]/(c^IntPart[p]*(b/2 + c*x)^(2*FracPart[p])), Int[(d + e*x)^m*(f + g*x)*(b/2 + c
*x)^(2*p), x], x] /; FreeQ[{a, b, c, d, e, f, g, m}, x] && EqQ[b^2 - 4*a*c, 0]

Rubi steps

\begin {align*} \int \frac {x^{7/2} (A+B x)}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx &=\frac {\left (b^4 \left (a b+b^2 x\right )\right ) \int \frac {x^{7/2} (A+B x)}{\left (a b+b^2 x\right )^5} \, dx}{\sqrt {a^2+2 a b x+b^2 x^2}}\\ &=\frac {(A b-a B) x^{9/2}}{4 a b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {\left (b^2 (A b-9 a B) \left (a b+b^2 x\right )\right ) \int \frac {x^{7/2}}{\left (a b+b^2 x\right )^4} \, dx}{8 a \sqrt {a^2+2 a b x+b^2 x^2}}\\ &=\frac {(A b-a B) x^{9/2}}{4 a b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {(A b-9 a B) x^{7/2}}{24 a b^2 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {\left (7 (A b-9 a B) \left (a b+b^2 x\right )\right ) \int \frac {x^{5/2}}{\left (a b+b^2 x\right )^3} \, dx}{48 a \sqrt {a^2+2 a b x+b^2 x^2}}\\ &=\frac {(A b-a B) x^{9/2}}{4 a b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {(A b-9 a B) x^{7/2}}{24 a b^2 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {7 (A b-9 a B) x^{5/2}}{96 a b^3 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {\left (35 (A b-9 a B) \left (a b+b^2 x\right )\right ) \int \frac {x^{3/2}}{\left (a b+b^2 x\right )^2} \, dx}{192 a b^2 \sqrt {a^2+2 a b x+b^2 x^2}}\\ &=\frac {35 (A b-9 a B) x^{3/2}}{192 a b^4 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {(A b-a B) x^{9/2}}{4 a b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {(A b-9 a B) x^{7/2}}{24 a b^2 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {7 (A b-9 a B) x^{5/2}}{96 a b^3 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {\left (35 (A b-9 a B) \left (a b+b^2 x\right )\right ) \int \frac {\sqrt {x}}{a b+b^2 x} \, dx}{128 a b^4 \sqrt {a^2+2 a b x+b^2 x^2}}\\ &=\frac {35 (A b-9 a B) x^{3/2}}{192 a b^4 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {(A b-a B) x^{9/2}}{4 a b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {(A b-9 a B) x^{7/2}}{24 a b^2 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {7 (A b-9 a B) x^{5/2}}{96 a b^3 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {35 (A b-9 a B) \sqrt {x} (a+b x)}{64 a b^5 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {\left (35 (A b-9 a B) \left (a b+b^2 x\right )\right ) \int \frac {1}{\sqrt {x} \left (a b+b^2 x\right )} \, dx}{128 b^5 \sqrt {a^2+2 a b x+b^2 x^2}}\\ &=\frac {35 (A b-9 a B) x^{3/2}}{192 a b^4 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {(A b-a B) x^{9/2}}{4 a b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {(A b-9 a B) x^{7/2}}{24 a b^2 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {7 (A b-9 a B) x^{5/2}}{96 a b^3 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {35 (A b-9 a B) \sqrt {x} (a+b x)}{64 a b^5 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {\left (35 (A b-9 a B) \left (a b+b^2 x\right )\right ) \operatorname {Subst}\left (\int \frac {1}{a b+b^2 x^2} \, dx,x,\sqrt {x}\right )}{64 b^5 \sqrt {a^2+2 a b x+b^2 x^2}}\\ &=\frac {35 (A b-9 a B) x^{3/2}}{192 a b^4 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {(A b-a B) x^{9/2}}{4 a b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {(A b-9 a B) x^{7/2}}{24 a b^2 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {7 (A b-9 a B) x^{5/2}}{96 a b^3 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {35 (A b-9 a B) \sqrt {x} (a+b x)}{64 a b^5 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {35 (A b-9 a B) (a+b x) \tan ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{64 \sqrt {a} b^{11/2} \sqrt {a^2+2 a b x+b^2 x^2}}\\ \end {align*}

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Mathematica [C]  time = 0.03, size = 79, normalized size = 0.26 \begin {gather*} \frac {x^{9/2} \left (9 a^4 (A b-a B)-(a+b x)^4 (A b-9 a B) \, _2F_1\left (4,\frac {9}{2};\frac {11}{2};-\frac {b x}{a}\right )\right )}{36 a^5 b (a+b x)^3 \sqrt {(a+b x)^2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(x^(7/2)*(A + B*x))/(a^2 + 2*a*b*x + b^2*x^2)^(5/2),x]

[Out]

(x^(9/2)*(9*a^4*(A*b - a*B) - (A*b - 9*a*B)*(a + b*x)^4*Hypergeometric2F1[4, 9/2, 11/2, -((b*x)/a)]))/(36*a^5*
b*(a + b*x)^3*Sqrt[(a + b*x)^2])

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IntegrateAlgebraic [A]  time = 32.09, size = 159, normalized size = 0.52 \begin {gather*} \frac {(a+b x) \left (\frac {\sqrt {x} \left (945 a^4 B-105 a^3 A b+3465 a^3 b B x-385 a^2 A b^2 x+4599 a^2 b^2 B x^2-511 a A b^3 x^2+2511 a b^3 B x^3-279 A b^4 x^3+384 b^4 B x^4\right )}{192 b^5 (a+b x)^4}-\frac {35 (9 a B-A b) \tan ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{64 \sqrt {a} b^{11/2}}\right )}{\sqrt {(a+b x)^2}} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[(x^(7/2)*(A + B*x))/(a^2 + 2*a*b*x + b^2*x^2)^(5/2),x]

[Out]

((a + b*x)*((Sqrt[x]*(-105*a^3*A*b + 945*a^4*B - 385*a^2*A*b^2*x + 3465*a^3*b*B*x - 511*a*A*b^3*x^2 + 4599*a^2
*b^2*B*x^2 - 279*A*b^4*x^3 + 2511*a*b^3*B*x^3 + 384*b^4*B*x^4))/(192*b^5*(a + b*x)^4) - (35*(-(A*b) + 9*a*B)*A
rcTan[(Sqrt[b]*Sqrt[x])/Sqrt[a]])/(64*Sqrt[a]*b^(11/2))))/Sqrt[(a + b*x)^2]

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fricas [A]  time = 0.47, size = 555, normalized size = 1.81 \begin {gather*} \left [\frac {105 \, {\left (9 \, B a^{5} - A a^{4} b + {\left (9 \, B a b^{4} - A b^{5}\right )} x^{4} + 4 \, {\left (9 \, B a^{2} b^{3} - A a b^{4}\right )} x^{3} + 6 \, {\left (9 \, B a^{3} b^{2} - A a^{2} b^{3}\right )} x^{2} + 4 \, {\left (9 \, B a^{4} b - A a^{3} b^{2}\right )} x\right )} \sqrt {-a b} \log \left (\frac {b x - a - 2 \, \sqrt {-a b} \sqrt {x}}{b x + a}\right ) + 2 \, {\left (384 \, B a b^{5} x^{4} + 945 \, B a^{5} b - 105 \, A a^{4} b^{2} + 279 \, {\left (9 \, B a^{2} b^{4} - A a b^{5}\right )} x^{3} + 511 \, {\left (9 \, B a^{3} b^{3} - A a^{2} b^{4}\right )} x^{2} + 385 \, {\left (9 \, B a^{4} b^{2} - A a^{3} b^{3}\right )} x\right )} \sqrt {x}}{384 \, {\left (a b^{10} x^{4} + 4 \, a^{2} b^{9} x^{3} + 6 \, a^{3} b^{8} x^{2} + 4 \, a^{4} b^{7} x + a^{5} b^{6}\right )}}, \frac {105 \, {\left (9 \, B a^{5} - A a^{4} b + {\left (9 \, B a b^{4} - A b^{5}\right )} x^{4} + 4 \, {\left (9 \, B a^{2} b^{3} - A a b^{4}\right )} x^{3} + 6 \, {\left (9 \, B a^{3} b^{2} - A a^{2} b^{3}\right )} x^{2} + 4 \, {\left (9 \, B a^{4} b - A a^{3} b^{2}\right )} x\right )} \sqrt {a b} \arctan \left (\frac {\sqrt {a b}}{b \sqrt {x}}\right ) + {\left (384 \, B a b^{5} x^{4} + 945 \, B a^{5} b - 105 \, A a^{4} b^{2} + 279 \, {\left (9 \, B a^{2} b^{4} - A a b^{5}\right )} x^{3} + 511 \, {\left (9 \, B a^{3} b^{3} - A a^{2} b^{4}\right )} x^{2} + 385 \, {\left (9 \, B a^{4} b^{2} - A a^{3} b^{3}\right )} x\right )} \sqrt {x}}{192 \, {\left (a b^{10} x^{4} + 4 \, a^{2} b^{9} x^{3} + 6 \, a^{3} b^{8} x^{2} + 4 \, a^{4} b^{7} x + a^{5} b^{6}\right )}}\right ] \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(7/2)*(B*x+A)/(b^2*x^2+2*a*b*x+a^2)^(5/2),x, algorithm="fricas")

[Out]

[1/384*(105*(9*B*a^5 - A*a^4*b + (9*B*a*b^4 - A*b^5)*x^4 + 4*(9*B*a^2*b^3 - A*a*b^4)*x^3 + 6*(9*B*a^3*b^2 - A*
a^2*b^3)*x^2 + 4*(9*B*a^4*b - A*a^3*b^2)*x)*sqrt(-a*b)*log((b*x - a - 2*sqrt(-a*b)*sqrt(x))/(b*x + a)) + 2*(38
4*B*a*b^5*x^4 + 945*B*a^5*b - 105*A*a^4*b^2 + 279*(9*B*a^2*b^4 - A*a*b^5)*x^3 + 511*(9*B*a^3*b^3 - A*a^2*b^4)*
x^2 + 385*(9*B*a^4*b^2 - A*a^3*b^3)*x)*sqrt(x))/(a*b^10*x^4 + 4*a^2*b^9*x^3 + 6*a^3*b^8*x^2 + 4*a^4*b^7*x + a^
5*b^6), 1/192*(105*(9*B*a^5 - A*a^4*b + (9*B*a*b^4 - A*b^5)*x^4 + 4*(9*B*a^2*b^3 - A*a*b^4)*x^3 + 6*(9*B*a^3*b
^2 - A*a^2*b^3)*x^2 + 4*(9*B*a^4*b - A*a^3*b^2)*x)*sqrt(a*b)*arctan(sqrt(a*b)/(b*sqrt(x))) + (384*B*a*b^5*x^4
+ 945*B*a^5*b - 105*A*a^4*b^2 + 279*(9*B*a^2*b^4 - A*a*b^5)*x^3 + 511*(9*B*a^3*b^3 - A*a^2*b^4)*x^2 + 385*(9*B
*a^4*b^2 - A*a^3*b^3)*x)*sqrt(x))/(a*b^10*x^4 + 4*a^2*b^9*x^3 + 6*a^3*b^8*x^2 + 4*a^4*b^7*x + a^5*b^6)]

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giac [A]  time = 0.38, size = 159, normalized size = 0.52 \begin {gather*} \frac {2 \, B \sqrt {x}}{b^{5} \mathrm {sgn}\left (b x + a\right )} - \frac {35 \, {\left (9 \, B a - A b\right )} \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )}{64 \, \sqrt {a b} b^{5} \mathrm {sgn}\left (b x + a\right )} + \frac {975 \, B a b^{3} x^{\frac {7}{2}} - 279 \, A b^{4} x^{\frac {7}{2}} + 2295 \, B a^{2} b^{2} x^{\frac {5}{2}} - 511 \, A a b^{3} x^{\frac {5}{2}} + 1929 \, B a^{3} b x^{\frac {3}{2}} - 385 \, A a^{2} b^{2} x^{\frac {3}{2}} + 561 \, B a^{4} \sqrt {x} - 105 \, A a^{3} b \sqrt {x}}{192 \, {\left (b x + a\right )}^{4} b^{5} \mathrm {sgn}\left (b x + a\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(7/2)*(B*x+A)/(b^2*x^2+2*a*b*x+a^2)^(5/2),x, algorithm="giac")

[Out]

2*B*sqrt(x)/(b^5*sgn(b*x + a)) - 35/64*(9*B*a - A*b)*arctan(b*sqrt(x)/sqrt(a*b))/(sqrt(a*b)*b^5*sgn(b*x + a))
+ 1/192*(975*B*a*b^3*x^(7/2) - 279*A*b^4*x^(7/2) + 2295*B*a^2*b^2*x^(5/2) - 511*A*a*b^3*x^(5/2) + 1929*B*a^3*b
*x^(3/2) - 385*A*a^2*b^2*x^(3/2) + 561*B*a^4*sqrt(x) - 105*A*a^3*b*sqrt(x))/((b*x + a)^4*b^5*sgn(b*x + a))

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maple [A]  time = 0.08, size = 368, normalized size = 1.20 \begin {gather*} -\frac {\left (-105 A \,b^{5} x^{4} \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )+945 B a \,b^{4} x^{4} \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )-420 A a \,b^{4} x^{3} \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )+3780 B \,a^{2} b^{3} x^{3} \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )-384 \sqrt {a b}\, B \,b^{4} x^{\frac {9}{2}}-630 A \,a^{2} b^{3} x^{2} \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )+5670 B \,a^{3} b^{2} x^{2} \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )+279 \sqrt {a b}\, A \,b^{4} x^{\frac {7}{2}}-2511 \sqrt {a b}\, B a \,b^{3} x^{\frac {7}{2}}-420 A \,a^{3} b^{2} x \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )+3780 B \,a^{4} b x \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )+511 \sqrt {a b}\, A a \,b^{3} x^{\frac {5}{2}}-4599 \sqrt {a b}\, B \,a^{2} b^{2} x^{\frac {5}{2}}-105 A \,a^{4} b \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )+945 B \,a^{5} \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )+385 \sqrt {a b}\, A \,a^{2} b^{2} x^{\frac {3}{2}}-3465 \sqrt {a b}\, B \,a^{3} b \,x^{\frac {3}{2}}+105 \sqrt {a b}\, A \,a^{3} b \sqrt {x}-945 \sqrt {a b}\, B \,a^{4} \sqrt {x}\right ) \left (b x +a \right )}{192 \sqrt {a b}\, \left (\left (b x +a \right )^{2}\right )^{\frac {5}{2}} b^{5}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^(7/2)*(B*x+A)/(b^2*x^2+2*a*b*x+a^2)^(5/2),x)

[Out]

-1/192*(279*(a*b)^(1/2)*A*b^4*x^(7/2)-2511*(a*b)^(1/2)*B*a*b^3*x^(7/2)+511*(a*b)^(1/2)*A*a*b^3*x^(5/2)-105*A*a
rctan(1/(a*b)^(1/2)*b*x^(1/2))*x^4*b^5-4599*(a*b)^(1/2)*B*a^2*b^2*x^(5/2)-384*(a*b)^(1/2)*B*b^4*x^(9/2)+945*B*
arctan(1/(a*b)^(1/2)*b*x^(1/2))*x^4*a*b^4-420*A*arctan(1/(a*b)^(1/2)*b*x^(1/2))*x^3*a*b^4+3780*B*arctan(1/(a*b
)^(1/2)*b*x^(1/2))*x^3*a^2*b^3+385*(a*b)^(1/2)*A*a^2*b^2*x^(3/2)-630*A*a^2*b^3*x^2*arctan(1/(a*b)^(1/2)*b*x^(1
/2))-3465*(a*b)^(1/2)*B*a^3*b*x^(3/2)+5670*B*a^3*b^2*x^2*arctan(1/(a*b)^(1/2)*b*x^(1/2))-420*A*a^3*b^2*x*arcta
n(1/(a*b)^(1/2)*b*x^(1/2))+3780*B*a^4*b*x*arctan(1/(a*b)^(1/2)*b*x^(1/2))+105*(a*b)^(1/2)*A*a^3*b*x^(1/2)-105*
A*a^4*b*arctan(1/(a*b)^(1/2)*b*x^(1/2))-945*(a*b)^(1/2)*B*a^4*x^(1/2)+945*B*a^5*arctan(1/(a*b)^(1/2)*b*x^(1/2)
))*(b*x+a)/(a*b)^(1/2)/b^5/((b*x+a)^2)^(5/2)

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maxima [A]  time = 1.62, size = 374, normalized size = 1.22 \begin {gather*} \frac {105 \, {\left (3 \, {\left (11 \, B a b^{5} - A b^{6}\right )} x^{2} + {\left (9 \, B a^{2} b^{4} + A a b^{5}\right )} x\right )} x^{\frac {9}{2}} + 30 \, {\left ({\left (359 \, B a^{2} b^{4} - 21 \, A a b^{5}\right )} x^{2} + {\left (61 \, B a^{3} b^{3} + 21 \, A a^{2} b^{4}\right )} x\right )} x^{\frac {7}{2}} + 20 \, {\left (66 \, {\left (11 \, B a^{3} b^{3} - A a^{2} b^{4}\right )} x^{2} + 13 \, {\left (9 \, B a^{4} b^{2} + A a^{3} b^{3}\right )} x\right )} x^{\frac {5}{2}} + 2 \, {\left (405 \, {\left (11 \, B a^{4} b^{2} - A a^{3} b^{3}\right )} x^{2} + 77 \, {\left (9 \, B a^{5} b + A a^{4} b^{2}\right )} x\right )} x^{\frac {3}{2}} + 7 \, {\left (27 \, {\left (11 \, B a^{5} b - A a^{4} b^{2}\right )} x^{2} + 5 \, {\left (9 \, B a^{6} + A a^{5} b\right )} x\right )} \sqrt {x}}{1920 \, {\left (a^{2} b^{9} x^{5} + 5 \, a^{3} b^{8} x^{4} + 10 \, a^{4} b^{7} x^{3} + 10 \, a^{5} b^{6} x^{2} + 5 \, a^{6} b^{5} x + a^{7} b^{4}\right )}} - \frac {35 \, {\left (9 \, B a - A b\right )} \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )}{64 \, \sqrt {a b} b^{5}} - \frac {7 \, {\left (3 \, {\left (11 \, B a b - A b^{2}\right )} x^{\frac {3}{2}} - 10 \, {\left (9 \, B a^{2} - A a b\right )} \sqrt {x}\right )}}{128 \, a^{2} b^{5}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(7/2)*(B*x+A)/(b^2*x^2+2*a*b*x+a^2)^(5/2),x, algorithm="maxima")

[Out]

1/1920*(105*(3*(11*B*a*b^5 - A*b^6)*x^2 + (9*B*a^2*b^4 + A*a*b^5)*x)*x^(9/2) + 30*((359*B*a^2*b^4 - 21*A*a*b^5
)*x^2 + (61*B*a^3*b^3 + 21*A*a^2*b^4)*x)*x^(7/2) + 20*(66*(11*B*a^3*b^3 - A*a^2*b^4)*x^2 + 13*(9*B*a^4*b^2 + A
*a^3*b^3)*x)*x^(5/2) + 2*(405*(11*B*a^4*b^2 - A*a^3*b^3)*x^2 + 77*(9*B*a^5*b + A*a^4*b^2)*x)*x^(3/2) + 7*(27*(
11*B*a^5*b - A*a^4*b^2)*x^2 + 5*(9*B*a^6 + A*a^5*b)*x)*sqrt(x))/(a^2*b^9*x^5 + 5*a^3*b^8*x^4 + 10*a^4*b^7*x^3
+ 10*a^5*b^6*x^2 + 5*a^6*b^5*x + a^7*b^4) - 35/64*(9*B*a - A*b)*arctan(b*sqrt(x)/sqrt(a*b))/(sqrt(a*b)*b^5) -
7/128*(3*(11*B*a*b - A*b^2)*x^(3/2) - 10*(9*B*a^2 - A*a*b)*sqrt(x))/(a^2*b^5)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {x^{7/2}\,\left (A+B\,x\right )}{{\left (a^2+2\,a\,b\,x+b^2\,x^2\right )}^{5/2}} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((x^(7/2)*(A + B*x))/(a^2 + b^2*x^2 + 2*a*b*x)^(5/2),x)

[Out]

int((x^(7/2)*(A + B*x))/(a^2 + b^2*x^2 + 2*a*b*x)^(5/2), x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**(7/2)*(B*x+A)/(b**2*x**2+2*a*b*x+a**2)**(5/2),x)

[Out]

Timed out

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